JEE Main 2024 Physics question
Two coherent monochromatic light beams of intensities I and 4I are superimposed. The difference between maximum and minimum possible intensities in the resulting beam is xI. The value of x is .
Answer: 8
Solution
= (√I + 2√I)² = 9I and = (2√I − √I)² = I, so the difference is 8I.