JEE Main 2024 Chemistry question
For the reaction at 298 K, 2A + B → C, ΔH = 400 kJ mol⁻¹ and ΔS = 0.2 kJ mol⁻¹ K⁻¹. The reaction will become spontaneous above K.
Answer: 2000
Solution
ΔG = ΔH − TΔS < 0 for T > 400/0.2 = 2000 K.
For the reaction at 298 K, 2A + B → C, ΔH = 400 kJ mol⁻¹ and ΔS = 0.2 kJ mol⁻¹ K⁻¹. The reaction will become spontaneous above K.
ΔG = ΔH − TΔS < 0 for T > 400/0.2 = 2000 K.