JEE Main 2024 Chemistry question
Consider the two different first order reactions given below: A + B → C (Reaction 1), P → Q (Reaction 2). The ratio of the half life of Reaction 1 : Reaction 2 is 5 : 2. If t₁ and t₂ represent the time taken to complete 2/3rd and 4/5th of reaction 1 and Reaction 2, respectively, then the value of the ratio t₁ : t₂ is × 10⁻¹ (nearest integer). [Given: log₁₀(3) = 0.477 and log₁₀(5) = 0.699]
Answer: 17
Solution
t = (t½/0.301) log[1/(1 − f)]: t₁/t₂ = (5/2)(log 3/log 5) = 2.5 × 0.477/0.699 = 1.706 = 17 × 10⁻¹.