JEE Main 2024 Mathematics question
If the locus of the point, whose distances from the point (2, 1) and (1, 3) are in the ratio 5 : 4, is ax² + by² + cxy + dx + ey + 170 = 0, then the value of a² + 2b + 3c + 4d + e is equal to:
Answer: (C)
Solution
16[(x − 2)² + (y − 1)²] = 25[(x − 1)² + (y − 3)²] gives 9x² + 9y² + 14x − 118y + 170 = 0. So
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