JEE Main 2020 Chemistry question
The gibbs energy change (in J) for the given reaction at = 1 M and 298K is: \mathrm{Cu(s)+Sn^{2+}(aq.)\rightarrow Cu^{2+}(aq.)+Sn(s)} ; V, V, Take F = 96500 C )
Answer: 96500
The gibbs energy change (in J) for the given reaction at = 1 M and 298K is: \mathrm{Cu(s)+Sn^{2+}(aq.)\rightarrow Cu^{2+}(aq.)+Sn(s)} ; V, V, Take F = 96500 C )