JEE Main 2020 Chemistry question
Not in JEE Main or NEET syllabus
The mass of gas adsorbed, x, per unit mass of adsorbate, m, was measured at various pressures, p. A graph between and log p gives a straight line with slope equal to 2 and the intercept equal to 0.4771. The value of at a pressure of 4 atm is : (Given log 3 = 0.4771)
Answer: 48
Solution
x/m = k·p² with log k = 0.4771, so k = 3 and x/m = 3 × 4² = 48 (the paper's working; its key prints 6.00).