JEE Main 2024 Physics question

PhysicsUnits and MeasurementJEE Main 2024

Young's modulus is determined by the equation given by Y = 49000 where M is the mass and ℓ is the extension of wire used in the experiment. Now error in Young modules (Y) is estimated by taking data from M–ℓ plot in graph paper. The smallest scale divisions are 5 g and 0.02 cm along load axis and extension axis respectively. If the value of M and ℓ are 500 g and 2 cm respectively then percentage error of Y is:

Answer: (C)

Solution

ΔY/Y = ΔM/M + Δℓ/ℓ = 5/500 + 0.02/2 = 0.01 + 0.01 = 2%.

Question ID VK-012307