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JEE Main 2024 Physics question

PhysicsMoving Charges and MagnetismJEE Main 2024

An electron with kinetic energy 5 eV enters a region of uniform magnetic field of 3 μT perpendicular to its direction. An electric field E is applied perpendicular to the direction of velocity and magnetic field. The value of E, so that electron moves along the same path, is NC⁻¹. (Given, mass of electron = 9 × 10⁻³¹ kg, electric charge = 1.6 × 10⁻¹⁹ C)

Answer: 4

Solution

The electron moves undeflected when qE = qvB: v = √(2K/m) = √(2 × 5 × 1.6 ×

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Question ID VK-012319