JEE Main 2024 Chemistry question
Combustion of glucose (C₆H₁₂O₆) produces CO₂ and water. The amount of oxygen (in g) required for the complete combustion of 900 g of glucose is: [Molar mass of glucose in g mol⁻¹ = 180]
Answer: (B)
Solution
C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O; 900 g = 5 mol needs 30 mol O₂ = 960 g.