JEE Main 2024 Mathematics question
The value of is .
Answer: 55
Solution
≈ 1 − kx²/2, so the product ≈ 1 − (1 + 2 + … + 10)x²/2 = 1 − 55x²/2. The limit is 2 × (55/2) = 55.
The value of is .
≈ 1 − kx²/2, so the product ≈ 1 − (1 + 2 + … + 10)x²/2 = 1 − 55x²/2. The limit is 2 × (55/2) = 55.