JEE Main 2024 Physics question

PhysicsNucleiJEE Main 2024

In a hypothetical fission reaction X → Y + Z + 3R. The identity of emitted particles (R) is:

Answer: (C)

Solution

Mass number: 236 − 141 − 92 = 3, so each R has A = 1; charge: 92 − 56 − 36 = 0, so R is a neutron.

Question ID VK-012389