JEE Main 2024 Physics question
A coil of negligible resistance is connected in series with 90 Ω resistor across 120 V, 60 Hz supply. A voltmeter reads 36 V across resistance. Inductance of the coil is:
Answer: (A)
Solution
I = 36/90 = 0.4 A; = √(120² − 36²) = 114.5 V; = 286.2 Ω; L = /(2π × 60) ≈ 0.76 H.