JEE Main 2024 Physics question
Two slits are 1 mm apart and the screen is located 1 m away from the slits. A light wavelength 500 nm is used. The width of each slit to obtain 10 maxima of the double slit pattern within the central maximum of the single slit pattern is ……….. × 10⁻⁴ m.
Answer: 2
Solution
The fringe width is β = λD/d = 0.5 mm. The central maximum of the single slit
See the full step-by-step solution
Create a free account to read the complete working, and practise questions like this in a timed test.
Create a free account