JEE Main 2024 Physics question
A body of mass M thrown horizontally with velocity v from the top of the tower of height H touches the ground at a distance of 100m from the foot of the tower. A body of mass 2M thrown at a velocity from the top of tower of height 4H will touch the ground at a distance of ……….m.
Answer: 100
Solution
Range = v√(2H/g). New range = (v/2)√(2 × 4H/g) = v√(2H/g) = 100 m.