JEE Main 2024 Chemistry question
Molality of an aqueous solution of urea is 4.44 m. Mole fraction of urea in solution is x × 10⁻³. Value of x is . (integer answer)
Answer: 74
Solution
In 1 kg water there are 55.55 mol of water and 4.44 mol of urea: = 4.44/(4.44 + 55.55) = 0.074 = 74 × 10⁻³.