JEE Main 2024 Chemistry question
Total number of unpaired electrons in the complex ion [Co(NH₃)₆]³⁺ and [NiCl₄]²⁻ is:
Answer: 2
Solution
[Co(NH₃)₆]³⁺ is low-spin d⁶ (0 unpaired) and tetrahedral [NiCl₄]²⁻ is d⁸ (2 unpaired): a total of 2.
Total number of unpaired electrons in the complex ion [Co(NH₃)₆]³⁺ and [NiCl₄]²⁻ is:
[Co(NH₃)₆]³⁺ is low-spin d⁶ (0 unpaired) and tetrahedral [NiCl₄]²⁻ is d⁸ (2 unpaired): a total of 2.