JEE Main 2024 Mathematics question
Let y = y(x) be the solution curve of the differential equation sec y + 2x sin y = x³ cos y, y(1) = 0. Then y(√3) is equal to:
Answer: (C)
Solution
Multiplying by sec y gives sec²y·y′ + 2x tan y = x³. With t = tan y: t′ + 2xt = x³, so t· =
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