JEE Main 2024 Mathematics question

The number of distinct real roots of the equation |x + 1||x + 3| − 4|x + 2| + 5 = 0, is .

Answer: 2

Solution

Put t = x + 2: |t² − 1| − 4|t| + 5 = 0. For |t| ≥ 1: t² − 4|t| + 4 = 0 gives |t| = 2, so x

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Question ID VK-012473