If (a_1+ib_1)(a_2+ib_2) (a_n+ib_n)=A+iB, then _ i=1 ^n ^ -1 ( b_i a_i ) is equal to

JEE Main Mathematics question

If (a_1+ib_1)(a_2+ib_2)\cdots(a_n+ib_n)=A+iB, then is equal to

Answer: (C)

The argument of a product is the sum of the arguments, so . Since (up to a multiple of

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Question ID VK-013987