NEET 2022 Chemistry question
What mass of 95% pure CaCO will be required to neutralise 50 mL of 0.5 M HCl solution according to the following reaction?
CaCO_3(s)+2HCl(aq)→CaCl_2(aq)+CO_2(g)+2H_2O(l)
[Calculate upto second place of decimal point]
Answer: (C)
Solution
HCl = 0.025 mol needs 0.0125 mol CaCO = 1.25 g pure; for 95% purity g.