JEE Main 2026 Mathematics question
Let the parabola y = x² + px + q passing through the point (1, −1) be such that the distance between its vertex and the x-axis is minimum. Then the value of p² + q² is:
Answer: (B)
Solution
q = −2 − p, and the vertex's y-coordinate is , whose magnitude is minimised at p = −2, giving q = 0 and p² + q² = 4.