JEE Main 2026 Mathematics question
If the area of the region bounded by 16x² − 9y² = 144 and 8x − 3y = 24 is A, then 3(A + is equal to .
Answer: 24
Solution
The hyperbola x²/9 − y²/16 = 1 and the line meet at x = 3 and x = 5. Integrating the
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