JEE Main 2026 Physics question

PhysicsOscillationsJEE Main 2026

The equation of motion of a particle is given by x = a sin cm. The particle will come to rest at time t₁ and it will have zero acceleration at time t₂. The t₁ and t₂ respectively are .

Answer: (A)

Solution

v = 0 when 50t + π/3 = π/2, giving t₁ = π/300 s. a = 0 when 50t + π/3 = π, giving t₂ = 2π/150 = π/75 s.

Question ID VK-015154