JEE Main 2026 Physics question
In a Young's double slit experiment, the intensity at some point on the screen is found to be times of the maximum of the interference pattern. The path difference between the interfering waves at this point is where λ is wavelength of the incident light. The value of x is .
Answer: 6
Solution
I = Imax cos²(δ/2) = (3/4)Imax gives δ/2 = π/6, so δ = π/3. Path difference = λδ/(2π) = λ/6, so x = 6.