JEE Main 2026 Chemistry question

ChemistryEquilibriumJEE Main 2026

At 25°C, 20.0 mL of 0.2 M weak monoprotic acid HX is titrated against 0.2 M NaOH. The pH of the solution (a) at the start of the titration (when NaOH has not been added) and (b) when 10 mL of NaOH is added respectively, are: Given: Ka = 5×10⁻⁴, pKa = 3.3, α << 1

Answer: (B)

Solution

(a) [H⁺] = √(Ka·C) = √(5×10⁻⁴ × 0.2) = 0.01, so pH = 2.0. (b) 10 mL of NaOH

See the full step-by-step solution

Create a free account to read the complete working, and practise questions like this in a timed test.

Create a free account

Question ID VK-015165