JEE Main 2026 Mathematics question
Let A be the set of first 101 terms of an A.P., whose first term is 1 and the common difference is 5 and let B be the set of first 71 terms of an A.P., whose first term is 9 and the common difference is 7. Then the number of elements in A ∩ B, which are divisible by 3, is:
Answer: (B)
Solution
A = {1 + 5i : 0 ≤ i ≤ 100} (largest 501) and B = {9 + 7j : 0 ≤ j ≤ 70} (largest 499). The common terms are the numbers ≡ 16 (mod 35): 16,
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