JEE Main 2026 Physics question

PhysicsUnits and MeasurementJEE Main 2026

The dimensional formula of (ε₀ = permittivity of vacuum and E = electric field) is MᵃLᵇTᶜ. The value of 2a − b + c = .

Answer: (B)

Solution

½ε₀E² is an energy density, with dimensions ML⁻¹T⁻². So a = 1, b = −1, c = −2 and 2a − b + c = 2 + 1 − 2 = 1.

Question ID VK-015210