JEE Main 2026 Physics question
The diameter of a wire measured by a screw gauge of least count 0.001 cm is 0.08 cm. The length measured by a scale of least count 0.1 cm is 150 cm. When a weight of 100 N is applied to the wire, the extension in length is 0.5 cm, measured by a micrometer of least count 0.001 cm. The error in the measured Young's modulus is α × 10⁹ N/m². The value of α is . (Ignore the contribution of the load to Young's modulus error calculation)
Answer: (B)
Solution
Y = 4FL/(πd²ΔL) = 5.97 × 10¹⁰ N/m². ΔY/Y = 2(0.001/0.08) + 0.1/150 +
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