JEE Main 2026 Physics question
The velocity of a particle is given as m/s. The magnitude of acceleration at point (1, 2, 4) is m/s².
Answer: (B)
Solution
= (−x)(−1)î + (2y)(2)ĵ + (−z)(−1)k̂ = (x, 4y, z). At (1, 2, 4): (1, 8, 4), so |a| = √81 = 9 m/s².