JEE Main 2026 Physics question

PhysicsLaws of MotionJEE Main 2026

A particle is rotating in a circular path and at any instant its motion can be described as . The angular acceleration of the particle after 10 seconds is rad/s².

Answer: (C)

Solution

θ = t⁴/8 − t³/3, ω = t³/2 − t² and α = 3t²/2 − 2t. At t = 10: 150 − 20 = 130 rad/s².

Question ID VK-015215