JEE Main 2026 Physics question
When a coil is placed in a time dependent magnetic field the power dissipated in it is P. The number of turns, area of the coil and radius of the coil wire are N, A and r respectively. For a second coils number of turns, area of the coil and radius of the coil wire are 2N, 2A and 3r respectively. When the first coil is replaced with second coil the power dissipated in it is √2αP. The value of α is .
Answer: (A)
Solution
P = ε²/R with ε = NA(dB/dt) and R ∝ (length of wire)/(wire area) ∝ N√A/r². So P ∝
See the full step-by-step solution
Create a free account to read the complete working, and practise questions like this in a timed test.
Create a free account