JEE Main 2026 Physics question
In single slit diffraction pattern, the wavelength of light used is 628 nm and slit width is 0.2 mm, the angular width of central maximum is α × 10⁻² degrees. The value of α is .
Answer: 36
Solution
The angular width is 2λ/a = 2 × 628 × 10⁻⁹/(0.2 × 10⁻³) = 6.28 × 10⁻³ rad = 0.36° = 36 × 10⁻² degrees.