JEE Main 2026 Physics question
1 μC charge moving with velocity m/s in the region of magnetic field T. The magnitude of force acting on it is √α × 10⁻⁶ N. The value of α is .
Answer: 171
Solution
= (10 − 9, 6 + 5, 3 + 4) = (1, 11, 7), of squared magnitude 1 + 121 + 49 = 171. So F = √171 × 10⁻⁶ N.