JEE Main 2026 Physics question
A uniform wire of length l of weight w is suspended from the roof with a weight of W at the other end. The stress in the wire at distance from the top is , where, A is the cross sectional area of the wire. The value of γ is .
Answer: 3
Solution
At l/3 from the top the wire below has weight 2w/3, so the stress is (W + 2w/3)/A = W/A + (2/3)(w/A) and γ = 3.