JEE Main 2026 Chemistry question

ChemistryThermodynamicsJEE Main 2026

Consider the following data: (i) 2Al(s) + 6HCl(aq) → Al₂Cl₆(aq) + 3H₂(g), ΔH = −1200 kJ/mol (ii) H₂(g) + Cl₂(g) → 2HCl(g), ΔH = −164 kJ/mol (iii) HCl(g) + aq → HCl(aq), ΔH = −83 kJ/mol (iv) Al₂Cl₆(s) + aq → Al₂Cl₆(aq), ΔH = −663 kJ/mol The enthalpy of formation of anhydrous solid Al₂Cl₆ is:

Answer: (D)

Solution

Δ = (i) + 3×(ii) + 6×(iii) − (iv) = −1200 + 3(−164) + 6(−83) − (−663) = −1200 − 492 − 498 + 663 = −1527 kJ mol⁻¹.

Question ID VK-015238