JEE Main 2026 Chemistry question

An electrochemical cell is constructed using half cells in the direction of spontaneous change: Fe(OH)₂(s) + 2e⁻ → Fe(s) + 2OH⁻(aq), E° = −0.88 V and AgBr(s) + e⁻ → Ag(s) + Br⁻(aq), E° = +0.07 V. Which of the following option is correct?

• (A)Overall reaction Fe(s) + 2OH⁻(aq) + 2AgBr(s) ⇌ Fe(OH)₂(s) + 2Ag(s) + 2Br⁻(aq)Correct
• (B) = −0.95 V
• (C)Fe is reduced in the electrochemical cell
• (D) is an extensive property