JEE Main 2026 Mathematics question
Let , where [·] is the greatest integer function. Then equals:
Answer: (B)
Solution
∫|sinx|dx over [−2,2] = 2−2cos2. [x sinx] is 0 on [0,x₀) and 1 on [x₀,2] where x₀sinx₀=1, so its (even) integral is
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