JEE Main 2026 Physics question
Two nuclei of mass number 3 combine with another nucleus of mass number 4 to yield a nucleus of mass number 10. If the binding energy per nucleon for the mass numbers 3, 4 and 10 are 5.6 MeV, 7.4 MeV and 6.1 MeV, respectively, then in the process, ΔMc² = MeV.
Answer: (C)
Solution
Total BE before = 2(3×5.6) + 1(4×7.4) = 33.6 + 29.6 = 63.2 MeV. BE after = 10×6.1 = 61 MeV. |ΔBE| = 2.2 MeV.