JEE Main 2026 Physics question
The velocity of a particle executing simple harmonic motion along x-axis is described as v² = 50 − x², where x represents displacement. If the time period of motion is s, the value of X is .
Answer: 44
Solution
Comparing with v² = ω²(A²−x²) gives ω = 1 rad/s, so T = 2π s. X = 7T = 14π ≈ 44.