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JEE Main 2026 Chemistry question

ChemistrySome Basic Concepts of ChemistryJEE Main 2026

2.0 g of a bromo hydrocarbon (X) was subjected to Carius analysis, gave 3.36 g of AgBr. The percentage of carbon in the compound (X) is 26.7%. Total number of carbon atoms in the empirical formula for compound (X) is . (Given molar mass in g mol⁻¹ H:1, C:12, Br:80, Ag:108)

Answer: 5

Solution

Moles AgBr = 3.36/188 = 0.01787, giving %Br ≈ 71.5%, so %H ≈ 1.8%. The mole ratio C:H:Br =

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Question ID VK-015332