JEE Main 2026 Chemistry question
The pH of a solution obtained by mixing 5 mL of 0.1 M NH₄OH solution with 250 mL of 0.1 M NH₄Cl solution is × 10⁻². (Nearest integer) Given: pKb(NH₄OH) = 4.74, log2 = 0.30, log3 = 0.48, log5 = 0.70
Answer: 756
Solution
Moles NH₄OH = 0.5 mmol, NH₄Cl = 25 mmol, ratio salt/base = 50. pOH =
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