JEE Main 2026 Mathematics question
Let S = {z ∈ ℂ : z² + 4z + 16 = 0}. Then is equal to:
Answer: (D)
Solution
The roots are z = −2 ± 2√3 i. |(−2+2√3i)+√3i|² = |−2+3√3i|² = 4+27 = 31. |(−2−2√3i)+√3i|² = |−2−√3i|² = 4+3 = 7. Sum = 38.
Let S = {z ∈ ℂ : z² + 4z + 16 = 0}. Then is equal to:
The roots are z = −2 ± 2√3 i. |(−2+2√3i)+√3i|² = |−2+3√3i|² = 4+27 = 31. |(−2−2√3i)+√3i|² = |−2−√3i|² = 4+3 = 7. Sum = 38.