JEE Main 2026 Mathematics question
In the expansion of , x > 0, if the term independent of x is (221)k, then k is equal to:
Answer: (A)
Solution
The term independent of x occurs at r=12: C(18,12)·9⁶·3⁻¹² = 18564. Dividing by 221 gives k = 84.
In the expansion of , x > 0, if the term independent of x is (221)k, then k is equal to:
The term independent of x occurs at r=12: C(18,12)·9⁶·3⁻¹² = 18564. Dividing by 221 gives k = 84.