JEE Main 2026 Physics question
A metal string A is suspended from a rigid support and its free end is attached to a block of mass M. Second block having mass 2M is suspended at the bottom of the first block using a string B. The area of cross sections of strings A and B are same. The ratio of lengths of strings of A to B is 2 and the ratio of their Young's moduli / is 0.5. The ratio of elongations in A to B is .
Answer: (D)
Solution
String A carries tension 3Mg (M+2M below it); string B carries 2Mg. Δ/Δ = /// = (3/2)(2)(2) = 6.