JEE Main 2026 Physics question
A diode has Zener voltage of 10 V and maximum power dissipation of 0.5 W, then the minimum resistance to be used in series with this diode for safety when it is connected to a 25 V power supply is Ω.
Answer: 300
Solution
= P/V = 0.5/10 = 0.05 A. Voltage across series resistor = 25−10 = 15 V. R = 15/0.05 = 300 Ω.