JEE Main 2026 Chemistry question

ChemistryElectrochemistryJEE Main 2026

An electrochemical cell, consist of the following two redox couples, Mˣ⁺(aq)/M(s) [E°red=+0.15 V] and Fe³⁺(aq)/Fe(s) [E°red=−0.036 V]. The cell EMF is recorded to be 0.2057 V. If the reaction quotient of the electrochemical reaction is found to be 10⁻², then the value of x is . (Nearest integer) [Given: M is a p-block metal and (2.303RT)/F = 0.059 V]

Answer: 2

Solution

E°cell = 0.15−(−0.036) = 0.186 V. Nernst: 0.2057 = 0.186 + (0.118/n),

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Question ID VK-015407