JEE Main 2026 Mathematics question
Let the eccentricity e of a hyperbola satisfy the equation 6e²−11e+3=0. If the foci of the hyperbola are (3,5) and (3,−4), then the length of its latus rectum is:
Answer: (C)
Solution
e=3/2 (>1). 2c=9 gives c=4.5, a=c/e=3, b²=c²−a²=45/4. Latus rectum=2b²/a=15/2.