JEE Main 2026 Physics question
A mass of 1 kg is kept on an inclined plane with 30° inclination with respect to horizontal plane and it is at rest initially. Then the whole assembly is moved up with constant velocity of 4 m/s. The work done by the frictional force in time 2 s is J. (Take g=10 m/s²)
Answer: (A)
Solution
With the block moving rigidly with the incline (vertically upward, constant velocity, zero net force), the static friction along the incline equals mg sinθ = 5
See the full step-by-step solution
Create a free account to read the complete working, and practise questions like this in a timed test.
Create a free account