JEE Main 2026 Physics question

PhysicsGravitationJEE Main 2026

A body of mass m is taken from the surface of earth to a height equal to twice the radius of earth (Rₑ). The increase in potential energy will be . (g is acceleration due to gravity at the surface of earth)

Answer: (D)

Solution

ΔPE=mgRh/(R+h). With h=2R: ΔPE=mgR(2R)/(3R)=2mgR/3.

Question ID VK-015441