JEE Main 2026 Physics question
Assuming the experimental mass of ¹²₆C as 12 u, the mass defect of ¹²₆C atom is MeV/c². (Mass of proton=1.00727u, mass of neutron=1.00866u, 1u=931.5 MeV/c²)
Answer: (B)
Solution
Δm=6(1.00727)+6(1.00866)−12=0.09558u. Energy=0.09558×931.5≈89.03 MeV.